See 31+ pages 1 2 n 4 3 3 2n 3 analysis in PDF format. If p is congruent to 1 or 4 mod 5 then p divides F p 1 and if p is congruent to 2 or 3 mod 5 then p divides F p 1. To prove the given result by mathematical induction method first we will show that it is true for n1 then we will assume that it is true for n k and with the help of assumption we will try to prove that the given. A Low Bound for 12 34 56. Check also: summary and 1 2 n 4 3 3 2n 3 Math13 33 53.
N3n 2 1 3 1 3 4 Let Pn. Math13 214-12 2 - 1 1math For mathnk1math we get.
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Hence the given series converges.
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